What force does water exert on the base of a tank of base area `1.5m^(2)` when it is filled with water upto a height of 1m `(rhoH_(2)o = 10^(3) kg//m^(3).P_(0) = 10^(5)Pa` and `g=10m//s^(2))`

Explanation

Pressure at the bottom of the container is P=`P_(0)+hrhog = 10^(5) +1xx10^(3)xx10= 1.1 x 10^(5)Pa`
Then force due to water on the base is `F_("base")=(1.1 xx 10(5)Pa 1.5m^(2))`
`=1.65xx10^(5)N`