Calculate the ratio of electric and gravita-tional forces between two electrons. (charge of the electron (e) `= 1.6 xx 10^(-19) c`, mass of the electron (m) `= 9.1 xx 10^(-31) kg, (1)/(4pi epsilon_(0)) = 9 xx 10^(19) Nm^(2)C^(-2)`, universal gravitational constant `G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)`)

Explanation

The electric force `Fe = (e^(2))/(4pi epsilon_(0) r^(2))`
The gravitational force `Fg = (Gm^(2))/(r^(2))`
`therefore (Fe)/(Fg) = (1)/(4 pi epsilon_(0)) xx (e^(2))/(m^(2)G)`
`= 9 xx 10^(9) xx ((1.6 xx 10^(-19))^(2))/((9.1 xx 10^(-31))^(2) xx 6.67 xx 10^(-11)) = 4.17 xx 10^(42)`