The escape velocity of projectile on the surface of earth is `11.2 Kms^(-1)`. If a body is projected out with thrice of this speed, find the speed of the body far away from the earth. Ignore the presence of other planets and sun.

Explanation

`v = sqrt(v_(p)^(2) - v_(e)^(2)) = sqrt((3V_(e))^(2) - v_(g)^(2))`
`= sqrt(8 xx 11.2) = 31.68 kms^(-1)`.