If two charged particles each of charge q mass m are connected to the ends of a rigid massless rod and is rotated about an axis passing through the centre and `bot` to length. Then find the ratio of magnetic moment to angular momentum

Explanation

`M=niA=2xxq/Tpi(l/2)^(2)`
`=2xx(qomega)/(2pi)(pil^(2))/4=(qomegal^(2))/4`
`L=2(mr^(2)omega)=2(m(l^(2))/4omega)=(ml^(2)omega)/2, M/L=q/(2m)`