If a straight conductor of length 40cm bent in the form of a square and the current 2A is allowed to pass through square, then find the magnetic induction at the centre of the square loop

Explanation

`B_("net")=4B_("side")`
`B_("net")=4(mu_(0))/(4pi)xxI/(L//2)(sin45^(@)+sin45^(@))`
`=4xx(mu_(0))/(4pi)xxI/(L//2)(sqrt2)=(mu_(0))/(4pi)(8sqrt(21))/L`
`=10^(-7)xx8sqrt2xx2xx10=16sqrt2muT`