A Long straight conductor carrying a current of 2 A is in parallel to another conductor of length 5 cm. and carrying a current 3A. They are separated by a distance of 10 cm. Calculate (a) B due to first conductor at second conductor (b) the force on the short conductor.

Explanation

Given, `i_(1)=2A,i_(2)=3A`
`r=10cm=10xx10^(-2)m,l_(2)=5cm`
a) `B=(mu_(0)i_(1))/(2pir)=2xx10^(-7)xx2/(10xx10^(2))=4xx10^(-6)` Tesla
b) `F=(mu_(0)i_(1)i_(2))/(2pir)l_(2)=2xx10^(-7)xx(2xx3)/(10xx10^(-2))xx5xx10^(-2)`
`=6xx10^(-7)N`