Two conductors each of length 12 m lie parallel to each other in air. The centre to center distance between two conductors is `15 xx 10^(-2)` m and the current in each conductor is 300 amperes. Determine the force in newton tending to pull the conductors together.

Explanation

Force between two conductors is given by
`F=(mu_(0))/(2pi)(i_(1)i_(2)l)/r`
Given `l=12m,r=15xx10^(-2)m`
`i_(1)=i_(2)=300A`
`thereforeF=2xx10^(-5)xx(300xx300xx12)/(15xx10^(-2))=1.44N`