The area of the coil in a moving coil galvanometer is 16 `cm^(2)` and has 20 turns. The magnetic induction is 0.2T and the couple per unit twist of the suspended wire is `10^(-6)` Nm per degree. If the deflection is 45° calculate the current passing through it.

Explanation

Given, A=`16cm^(2)=16xx10^(-4)m^(2)`
`B=0.2T,N=20,C=10^(-6)Nm//`degree, `theta=45^(@)`
From, `Ctheta=BiAN`
`i=(Ctheta)/("BAN")=(10^(-6)xx45)/(0.2xx16xx10^(-4)xx20)=7.03xx10^(-3)`