An electron of mass m and charge e is accelerated by a potential difference V. It then enters a uniform magnetic field B applied perpendicular to its path. The radius of the circular path of the electron is

Options

A. `r=((2mV)/(eB^(2)))^(1//2)`
B. `r=((2meV)/(B^(2)))^(1//2)`
C. `r=((2mB)/(eV^(2)))^(1//2)`
D. `r=((2B^(2)V)/(em))^(1//2)`

Answer

A