Home
Class 12
PHYSICS
Simplify Y = AB+ABC +barAB+ AbarBC using...

Simplify `Y = AB+ABC +barAB+ AbarBC` using Boolean Algebra. Draw the resultant simplified logic circuit.

Text Solution

Verified by Experts

Given `Y=AB+ABC+barAB+AbarBC`
`Y=(A+barA)B+AC(B+barB)=B+AC (because B+barB=1)`
Logic Circuit is shown below.
Promotional Banner

Topper's Solved these Questions

  • LOGIC GATES

    AAKASH SERIES|Exercise Exercise (Short Answer)|9 Videos
  • LOGIC GATES

    AAKASH SERIES|Exercise Exercise (Very Short Answer)|16 Videos
  • LAWS OF MOTION

    AAKASH SERIES|Exercise PRACTICE EXERCISE|98 Videos
  • MAGNETISM

    AAKASH SERIES|Exercise PROBLEMS (LEVEL-II)|13 Videos

Similar Questions

Explore conceptually related problems

Simplify the following using laws of exponents : a^x xx a^y xx a^z .

ABC is a right triangle right angled at A. BCED,ACFG and ABMN are squares on the sides BC,CA and AB respectively. Line segments AX bot DE meets BC at Y and DE at X. Join AD,AE also BF and CM Show that ar(BCED)=ar(ABMN)+ar(ACFG) Can you write the result in words? This is a famous theorem of Pythagoras. You shall learn a simple proof in this theorem in class X.

Simplify the following using the law a^m xx b^m = (ab)^m : a^8 xx b^8 .

Simplify the following using the law a^m xx b^m = (ab)m , (2x3)^4

Draw the logic circuit corresponding to the Boolean expression. Y=AB+barBC .

Simplify the following using the law a^m xx b^m = (ab)^m : x^p xx y^p .