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A body moves along a circular path of ra...

A body moves along a circular path of radius `5m`. The coefficient of friction between the surface of the path and the body is `0.5`. The angular velocity in `rad//s` with which the body should move so that it does not leave the path is `(g-10m//s^(-2))`

A

4

B

3

C

2

D

1

Text Solution

Verified by Experts

The correct Answer is:
D
Here `, mu= 0.5 , r= 5 m, g = 10 ms^(-2)`
The frictional force provides the centripetal force
` therefore ( mv^2)/( r ) = mu mg or v^2 = mu rg `
` or v= sqrt( mu r g) or v^2 = mu rg `
As ` v=r omega therefore = (v )/( r ) =( 5 ms^(-1)) /( 5m ) = 1 rad s^(-1)`
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