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A motorcycle moving with a velocity of 7...

A motorcycle moving with a velocity of 72 km `h^(-1)` on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 m. The acceleration due to gravity is `10 ms^(-2)`. In order to avoid skidding, he must not bent with respect to the vertical plane by an angle greater than

A

`theta = tan^(-1) (2) `

B

`theta = tan ^(-1) (6) `

C

` theta tan ^(-1) (4)`

D

` theta = tan^(-1) ( 25.92)`

Text Solution

Verified by Experts

The correct Answer is:
A
Using the formula, for motorcycle not to skid
` theta = tan^(-1) ""( v^2)/(rg)`
here ` r= 20 m , v = 72 km h^(-1) = 72 xx (5)/(18) = 20 ms^(-1)`
` therefore theta = tan^(-1) (( 20 xx 20)/( 20 xx 10)) or theta = tan^(-1) (2)`
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