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A stone of mass 2 kg is tied to a string...

A stone of mass 2 kg is tied to a string of length 0.5 m. If the breaking tension of the string is 900 N, then the maximum angular velocity, the stone can have in uniform circular motion is

A

`30 rad s^(-1)`

B

`20 rad s^(-1)`

C

`10 rad s^(-1)`

D

`40 rad s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Here ,
Mass of the stone `,m= 2 kg `
Length of the string ` r= 0.5 m`
Breaking tension ` T = 900 N`
As ` T= m r omega^2`
` therefore omega^2 = (T) /(mr) = ( 900 )/(2 xx0.5 ) =900`
` or omega = 30 rad s^(-1)`
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