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The current flowing through 10 Omega res...

The current flowing through `10 Omega` resistor in the circuit shown in the figure is
 

A

50 mA

B

20 mA

C

40 mA

D

40 mA

Text Solution

Verified by Experts

The correct Answer is:
D
In the given circuit, junction diode `D_(1)` is forward biased and will conduct whereas junction diode `D_(2)` is reverse biased and will not conduct. Therefore current through `10Omega` resistor is `I=(2V)/(10Omega+15Omega)=0.08A=80mA`
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