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When the voltage drop across a p.n junct...

When the voltage drop across a `p.n` junction diode is increased from `0.65V` to `0.70V`, the change in the diode current is `5mA`. What is the dynamic resistance of the diode?

A

`20Omega`

B

`50Omega`

C

`10Omega`

D

`80Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
Dynamic resistance, `r_(d)=(DeltaV)/(DeltaI)`
`r_(d)=(0.7V-0.65V)/(5xx10^(-3)A)=(0.05xx1000)/(5)Omega=10Omega`
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