From the Zener diode circuit shown in figure, the current through the Zener diode is

Options

A. 34 mA
B. 31.5 mA
C. 36.5 mA
D. 2.5 mA

Answer

B

Explanation

Here, `R_(L )=20xx10^(3)Omega, V_(i)=220 V,`
Zener voltage, `V_(Z )=50V`
Load current,
`I_(L )=(V_(Z ))/(R_(L ))=(50)/(20xx10^(3))`
`=2.5xx10^(-3)A`
Current through R,
`I=(220-50)/(5xx10^(3))=34xx10^(-3)A`
Zener current, `I_(Z)=I-I_(L)=34xx10^(-3)-2.5xx10^(-3)=31.5mA`