A zener diode has a contact potential of 1 V in the absence of biasing. It undergoes Zener breakdown for an electric field of `10^(6)` V/m at the depletion region of p-n junction. If the width of the depletion region is 2.5 `mu`m, what should be the reverse biased potential for the Zener breakdown to occur ?

Options

A. 3.5 V
B. 2.5 V
C. 1.5V
D. 0.5 V

Answer

B

Explanation

The break down field of the Zener diode `=10^(6)V//m`.
The width of the deplection region `=2.5xx10^(-6)m.`
`therefore" "V_("breakdown")=Exxd=10^(6)xx2.5xx10^(-6)V=2.5V`