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In an NPN transistor the collector curre...

In an `NPN` transistor the collector current is `24 mA`. If `80%` of electrons reach collector it base current in `mA` is

A

36

B

26

C

16

D

6

Text Solution

Verified by Experts

The correct Answer is:
D
Here, `(80)/(100)I_(E)=24mA or I_(E)=(24xx100)/(80)mA`
`I_(B)=(20)/(100)I_(E)=(20)/(100)xx(24xx100)/(80)mA=6mA`.
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