In the cuircuit shown here the transistor used has a current gain `beta=100`. What should be the bias resistor `R_(BE)` so that `V_(CE)=5V("neglect "V_(BE))`

Options

A. `200xx10^(3)Omega`
B. `1xx10^(6)Omega`
C. `500Omega`
D. `2xx10^(3)Omega`

Answer

A

Explanation

Applying Kirchoff.s
law to mesh ADCEFA
`V_(C C)=10=I_(C )xx10^(3)+V_(CE )`
`10=I_(C )xx10^(3)+5`
`I_(C )=5xx10^(-3)A" …..(i)"`
Applying Kirchoff.s law to mesh AGBEFA
`I_(B)xxR_(B)+V_(BE)=V_(C C)=10V`
`I_(B)xxR_(B)=10" ....(ii)"`
`5xx10^(-5)xxR_(B)=10`
`R_(B)=2xx10^(5)Omega=200xx10^(3)Omega" "(because beta=(I_(C ))/(I_(B)))`