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A transistor is connected in a common em...

A transistor is connected in a common emitter configuration.
The collector supply is 8 V and the voltage drop across a resistor of `800 Omega ` in
the collector circuit is 0.5 V. If the current gain factor `(alpha) ` is 0.96 , Find the base
current.

A

`26mA`

B

`30muA`

C

`36muA`

D

`40muA`

Text Solution

Verified by Experts

The correct Answer is:
A
`beta=(alpha)/(1-alpha)=(0.96)/(1-0.96)=24`
The collector current, `I_(C )` is given by
`I_(C )=(V_(C ))/(r)=(0.5V)/(800Omega)=0.625xx10^(-3)A`
`I_(B)=(I_(C ))/(beta)=(0.625xx10^(-3))/(24)=26xx10^(-6)A=26muA`
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