If `alpha and beta` are the current gain in the CB and CE configurations respectively of the transistor circuit, then `(beta-alpha)/(alphabeta)=`

Options

A. zero
B. 1
C. 2
D. 0.5

Answer

B

Explanation

Since `beta=(alpha)/(1-alpha)" "therefore alpha beta=(alpha^(2))/(1-alpha)" ….(i)"`
`beta-alpha=(alpha)/(1-alpha)-alpha or beta-alpha=(alpha^(2))/(1-alpha)" ….(ii)"`
`therefore(beta-alpha)/(alpha beta)=((alpha^(2))/(1-alpha))((1-alpha)/(alpha^(2)))=1`