In a transistor amplifier `beta = 62, R_(L) = 5000 Omega` and internal resistance of the transistor is `500 Omega`. Its power amplification will be.

Options

A. 6200
B. 45850
C. 38440
D. 15320

Answer

C

Explanation

Given : `beta=62, R_(L)=5000Omega, R_(i)=500Omega`
Voltage amplification, `A_(V)=beta(R_(L))/(R_(i))=62xx(5000)/(500)=620`
Power amplification, `A_(P)=beta^(2)=(R_(L))/(R_(i))=(62)^(2)xx(5000)/(500)=38440`