The input resistance of a silicon transistor is `665Omega`. Its base current is changed by `15muA` which results in the change in collector current by `2mA`. This transistor is used as a common emitter amplifier with a load resistance of `5kOmega`. What is the voltage gain of the amplifier.

Options

A. 1002.5
B. 1232.8
C. 7235.9
D. 9879.3

Answer

A

Explanation

Given : `R_(i)=665Omega`
`DeltaI_(B)=15muA=15muA=15xx10^(-6)A, DeltaI_(C )=2mA=2xx10^(-3)A`
`R_(L )=5kOmega=5xx10^(3)Omega`
`beta=(DeltaI_(C))/(DeltaI_(B))=(2xx10^(-3))/(15xx10^(-6))=(400)/(3)`
Voltage gain, `A_(V)=beta(R_(L))/(R_(i)) rArr A_(V)=(400)/(3)xx(5xx10^(3))/(665)=1002.5`