In a common emitter amplifier, using output reisistance of `5000` ohm and input resistance fo `2000`ohm, if the peak value of input signal voltage is `10 m V` and `beta=50`, then the peak value of output voltage is

Options

A. `5xx10^(-6)V`
B. `12.5xx10^(-4)V`
C. `1.25V`
D. 125 V

Answer

C

Explanation

Voltage gain, `A_(V)=(V_(0))/(V)=beta(R_(o))/(r) or V_(o)=V_(i)xxbeta(R_(o))/(R_(i))`
Substituting the values of we get,
therefore `V_(o)=10xx50xx(5000)/(2000)=1250mV=1.25V`