For a common emitter amplifier, the audio frequency voltage across the collector resistance `2kOmega` is 2V. If the current amplication factor of the transistor is 200, and the base resistance is `1.5 kOmega`, the input signal voltage and base current are

Options

A. `0.1 V and 1muA`
B. `0.15V and 10muA`
C. 0.015 V and 1 A
D. 0.0075 V and `5muA`

Answer

D

Explanation

Here, `V_(o)=2V, R_(o)=2kOmega, R_(i)=1.5kOmega, beta=200`
`A_(V)=(V_(o))/(V_(i))=beta(R_(o))/(R_(i)) or V_(i)=(V_(o)R_(i))/(betaR_(o))=(2Vxx1.5kOmega)/(200xx2kOmega)=0,0075V`
`I_(C )=(V_(o))/(R_(o))=(2V)/(2kOmega)=1mA`
`I_(B)=(I_(C ))/(beta)=(1mA)/(200)=0.005mA=5xx10^(-6)A=5muA`