If `beta, R_L and r` are the ac current gain, load resistance and the input resistance of a transistor respectively in CE configuration, the voltage and the power gains respectively are

Options

A. `beta(R_(L))/(r) and beta^(2)(R_(L))/(r)`
B. `beta(r)/(R_(L)) and beta^(2)(r)/(R_(L ))`
C. `beta(R_(L))/(r) and beta((R_(L))/(r))^(2)`
D. `beta(r)/(R_(L)) and beta((r)/(R_(L)))^(2)`

Answer

A

Explanation

Voltage gain = current gain `xx` resistance gain
`=betaxx("output resistance")/("input resistance")=betaxx(R_(L))/(r)`
Power gain = voltage gain `xx` current gain
`beta=(R_(L))/(r)xxbeta=beta^(2)(R_(L))/(r)`