In the given figure, a diode `D` is connected to an external resistance `R=100 Omega` and an emf of `3.5 V`. If the barrier potential developed across the diode is `0.5 V`, the current in the circuit will be :

Options

A. 20 mA
B. 35 mA
C. 30 mA
D. 40 mA

Answer

C

Explanation

The potential difference across the resistance R is
`V=3.5V-0.5V=3V`
By Ohm.s law
The current in the circuit is
`I=(V)/(R )=(3V)/(100Omega)`
`=3xx10^(-2)A=30xx10^(-3)A=30mA`