A n-p-n transisitor is connected in common emitter configuration in a given amplifier. A load resistance of `800 Omega` is connected in the collector circuit and the voltage drop across it is `0.8 V`. If the current amplification factor is `0.96` and the input resistance of the circuits is `192 Omega`, the voltage gain and the power gain of the amplifier will respectively be

Answer

C

Explanation

Here, `R_(0)=800 Omega, R_(i)=192Omega,`
current gain, `beta=0.96`
Voltage gain = Current gain `xx` Resistance gain `=0.96xx(800)/(192)=4`
Power gain `=["Currrent gain"]xx["Voltage gain"]=0.96xx4=3.84`