The given circuit has two ideal diodes connected as show in the figure. The current flowing through the resistance `R_(1)` will be

Options

A. 2.5 A
B. 10.0 A
C. 1.43 A
D. 3.13 A

Answer

A

Explanation

Diode `D_(1)` is reverse biased so, it will block the current and diode `D_(2)` is forward biased, so it will pass the current. Hence, equivalent circuit becomes as shown in the figure.
Current in the circuit = Current flowing through the resitance
`R_(1)=(10)/(2+2)=2.5A`