Match column I with column II and select the correct option from the given codes.
`{:(" Column I",," Column II"),(A."""Glut ",,(i)"Intercellular ground substance"),(B."" "Antibody",,(ii)"Enzyme"),(C."" "Collagen",,(iii)"Hormone"),(D."""Trypsin",,(iv)"Fights infectious agents"),(E."""Insulin",,(v) "Enables glucose transport in cells"):}`

Options

A. `A-(i), B-(ii), C-(iii), D-(iv), E-(v)`
B. `A-(v), B-(iv), C-(i), D-(ii), E-(iii)`
C. `A-(v), B-(iv), C-(iii), D-(ii), E-(i)`
D. `A-(ii), B-(i), C-(iv), D-(v), E-(iii)`

Answer

To solve the matching question, we need to pair the items from Column I with their appropriate descriptions in Column II. Let's analyze each item step by step:

### Step 1: Analyze "Glut"
- **Glut** refers to glucose transporters, which help in the transport of glucose into cells.
- **Match:** Glut matches with (v) "Enables glucose transport in cells".

### Step 2: Analyze "Antibody"
- **Antibody** is a protein produced by the immune system that binds to antigens (foreign substances) and helps to fight infections.
- **Match:** Antibody matches with (iv) "Fights infectious agents".

### Step 3: Analyze "Collagen"
- **Collagen** is the most abundant protein in animals and serves as a major component of the extracellular matrix, providing structural support.
- **Match:** Collagen matches with (i) "Intercellular ground substance".

### Step 4: Analyze "Trypsin"
- **Trypsin** is an enzyme that breaks down proteins into smaller peptides. It is produced in the pancreas and is involved in digestion.
- **Match:** Trypsin matches with (ii) "Enzyme".

### Step 5: Analyze "Insulin"
- **Insulin** is a hormone produced by the pancreas that regulates glucose levels in the blood.
- **Match:** Insulin matches with (iii) "Hormone".

### Summary of Matches:
- A (Glut) → (v) Enables glucose transport in cells
- B (Antibody) → (iv) Fights infectious agents
- C (Collagen) → (i) Intercellular ground substance
- D (Trypsin) → (ii) Enzyme
- E (Insulin) → (iii) Hormone

### Final Answer:
The correct matching is:
- A → v
- B → iv
- C → i
- D → ii
- E → iii

Thus, the correct option is **B**.

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