If a tissue has at a given time 1024 cells, how many cycles of mitosis had the original paraental single cell undergone?

Options

A. 512
B. 10
C. 1024
D. 256

Explanation

To solve the question of how many cycles of mitosis the original parental single cell has undergone to produce 1024 cells, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Problem**: We need to determine how many cycles of mitosis are required to produce 1024 cells from a single parental cell.

2. **Recall the Mitosis Process**: Each cycle of mitosis results in the doubling of the number of cells. Therefore, if we start with one cell, after one cycle of mitosis, we will have 2 cells; after two cycles, we will have 4 cells; after three cycles, we will have 8 cells, and so on.

3. **Set Up the Equation**: The relationship between the number of cycles (n) and the number of cells can be expressed as:
\[ \text{Number of cells} = 2^n \]
where \( n \) is the number of cycles of mitosis.

4. **Substitute the Given Value**: We know that the number of cells is 1024. Therefore, we can set up the equation:
\[ 2^n = 1024 \]

5. **Solve for n**: To find \( n \), we need to express 1024 as a power of 2. We know that:
\[ 2^{10} = 1024 \]
Hence, we can equate:
\[ n = 10 \]

6. **Conclusion**: The original parental single cell has undergone 10 cycles of mitosis to produce 1024 cells.

### Final Answer:
The number of cycles of mitosis that the original parental cell has undergone is **10**.

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