Select the incorrectly matched pair.

Options

A. Phragmoplast - Peristent spindle
B. Reductional division - Meiosis I
C. Equational division - Meiosis II
D. Crossing over - Non-homologous chromosomes

Answer

To solve the question of selecting the incorrectly matched pair, we will analyze each pair provided.

### Step-by-Step Solution:

1. **Identify the first pair: Phragmoplast and Persistent Spindle**
- The phragmoplast is indeed linked with the persistent spindle as it is formed from the remnants of the spindle apparatus during cell division.
- **Conclusion**: This pair is correctly matched.

2. **Identify the second pair: Reductional Division and Meiosis I**
- Reductional division refers to the process where the chromosome number is halved. This occurs during Meiosis I, where the homologous chromosomes are separated.
- **Conclusion**: This pair is correctly matched.

3. **Identify the third pair: Equational Division and Meiosis II**
- Equational division is the term used for Meiosis II, where the two daughter cells from Meiosis I divide again without reducing the chromosome number, resulting in four haploid cells.
- **Conclusion**: This pair is correctly matched.

4. **Identify the fourth pair: Crossing Over and Non-Homologous Chromosomes**
- Crossing over is the exchange of genetic material that occurs between homologous chromosomes during prophase I of Meiosis I. It does not occur between non-homologous chromosomes.
- **Conclusion**: This pair is incorrectly matched.

### Final Answer:
The incorrectly matched pair is **Crossing Over with Non-Homologous Chromosomes**.

---