Refer the given equation.
`2(C_(51)H_(98)O_(6)) + 145O_(2) rarr 102CO_(2) +98H_(2)O +` Energy The RQ in this case is

Options

A. 1
B. 0.7
C. 1.45
D. 1.62

Explanation

To determine the Respiratory Quotient (RQ) from the given equation, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Equation**: The equation provided is:
\[ 2(C_{51}H_{98}O_{6}) + 145O_{2} \rightarrow 102CO_{2} + 98H_{2}O + \text{Energy} \]
This represents the respiration of a specific organic compound (in this case, a type of fat).

2. **Identify the Components**:
- The substrate being metabolized is \(C_{51}H_{98}O_{6}\), which is a type of fat (specifically tri-palmitin).
- The products of the reaction include carbon dioxide (\(CO_{2}\)) and water (\(H_{2}O\)), along with energy.

3. **Calculate the RQ**:
- RQ is defined as the ratio of the volume of carbon dioxide produced to the volume of oxygen consumed during respiration.
- The formula for RQ is:
\[ RQ = \frac{\text{CO}_{2} \text{ produced}}{\text{O}_{2} \text{ consumed}} \]

4. **Substitute the Values**:
- From the equation, we see that 102 moles of \(CO_{2}\) are produced and 145 moles of \(O_{2}\) are consumed.
- Therefore, substituting these values into the RQ formula gives:
\[ RQ = \frac{102}{145} \]

5. **Calculate the RQ Value**:
- Performing the division:
\[ RQ = \frac{102}{145} \approx 0.7034 \]

6. **Identify the Type of Substrate**:
- Since the substrate is a fat, we can also refer to the known RQ value for fats, which is approximately 0.7.

7. **Conclusion**:
- Thus, the RQ for the given reaction is approximately 0.7.

### Final Answer:
The RQ in this case is approximately **0.7**.