Home
Class 11
BIOLOGY
Assertion: Renal threshold of glucose is...

Assertion: Renal threshold of glucose is said to be 180 mg/100 mL
Reason: Glucose starts appearing in the urine when its blood level exceeds 180 mg/100 mL of blood

A

If both assertion and reason are true and reason is the correct explanation of assertion

B

if both assertion and reason are true but reason is not the correct explanation of assertion.

C

if assertion is true but reason is false

D

if both assertion and reason are false.

Text Solution

Verified by Experts

The correct Answer is:
A

Renal threshold of a substance is its highest concentration in the blood upto which it is totally reabsorbed from the glomerular filtrate. Renal threshold of glucose is about 180 mg/ 10 mL. Glucose is reabsorbed and does not appear in the urine as long as its blood level does not exceed 180 mg/ 100 mL.
Promotional Banner

Topper's Solved these Questions

  • EXCRETORY PRODUCTS AND THEIR ELIMINATION

    NCERT FINGERTIPS ENGLISH|Exercise Excretory Products And Their Elimination|133 Videos
  • EXCRETORY PRODUCTS AND THEIR ELIMINATION

    NCERT FINGERTIPS ENGLISH|Exercise Excretory Products And Their Elimination|133 Videos
  • DIGESTION AND ABSORPTION

    NCERT FINGERTIPS ENGLISH|Exercise Digestion And Absorption|137 Videos
  • LOCOMOTION AND MOVEMENT

    NCERT FINGERTIPS ENGLISH|Exercise Locomotion And Movement|139 Videos

Similar Questions

Explore conceptually related problems

Blood test ofa person shows glucose level to be 130 mg per 100 ml of blood. The urine of this person will

The concentration of glucose in plasma is 100 mg/100 mL and the GFR is 125 mL/min. How much glucose is filtered per minute?

At 27^(@)C,a1.2% solution ( wt.//"vol.") of glucose is isotonic with 4.0g//"litre" of urea solution. Find the molar mass of urea, if the molar mass of glucose is 180 . Also report the osmotic pressure of solution if 100mL of each are mixed at 27^(@)C . ( R=0.082 L atm "mol"^(-1)K^(-1) , Molar mass of glucose =180g//"mole" )

Assertion : A sigmoid curve is obtained when percentage saturation of haemoglobin with O_(2) is plotted against the PO_(2) . Reason : Every 100 mL of oxygenated blood can deliver around 5mL of O_(2) to the tissues under normal physiological conditions.

Normal level of haemoglobin per 100 ml of blood in a woman is

Assertion: 100 ml of blood delivers 5 ml O_(2) to tissues in normal conditions. Reason: One molecule of Hb can bind with 4 molecules of O_(2)

Alcohol level in blood is determined by the reaction with K_2Cr_2O_7 solution in acidic medium. Calculate the blood level in mass percent if 10 " mL of " 0.05 M solution of K_2Cr_2O_7 is required for the reaction of a 10.0 g sample of blood.

A patient complains of constant thirst, excessive passing of urine and low blood pressure. When the doctor checked the patients blood glucose and blood insulin level, the level were normal or slightly low. The doctor diagnosed the condition as diabetes insipidus. But he decided to measure one more hormone in patients blood. Which hormone does the doctor intend to measure?

A tube of uniform cross-sectional area 1 cm^(2) is closed at one end with semi-permeable membrane. A solution of 5 g glucose per 100 mL is placed inside the tube and is dipped in pure water at 27^(@)C . When equilibrium is established, calculate: a. The osmotic pressure of solution. b.The height developed in vertical column. Assume the density of final glucose solution 1 g mL^(-1)

Assertion :- Major part of CO_(2) is transported in the form of sodium bicarbonate. Reason :- 0.3 ml of CO_(2) is transported per 100ml of blood in dissolved state in plasma of blood.