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Assertion (A): The electrolysis of NaCl ...

Assertion `(A):` The electrolysis of `NaCl` solution gives `H_(2)(g)` at cathode and `Cl_(2)(g)` at anode.
Reason `(R) : Cl_(2)` has higher oxidation potential than `H_(2)O`

A

If both assertion and reason are true and reason is the correct explanation of assertion.

B

If both assertion and reason are true but reason is not the correct explanation of assertion.

C

If assertion is true but reason is false.

D

If both assertion and reason are false.

Text Solution

Verified by Experts

The correct Answer is:
b

When an offspring is produced by a single parent without the involvement of gamete formation, the reproduction is called asexual reproduction. As a result, the offspring produced are not only similar to one another but are also exact copies of their parent. Such a group of morphologically and genetically similar individuals are called clones.
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The electrolysis of a solution resulted in the formation of H_2 (g) at the cathode and Cl_(2) (g) at anode. The solution is :

Assertion(A) Electrolysis of NaCl solution gives chlorine at anode instead of O_(2) . Reason(R) Formation of oxygen at anode requires over voltage.

Assertion (A): The enthalpy of formation of H_(2)O(l) is greater than that of H_(2)O(g) . Reason (R ) : Enthalpy change is negative for the condensation reaction H_(2)O(g) rarr H_(2)O(l) .

The passage of current through a solution of certain electrolyte results in the evolution of H_2 (g) at cathode and Cl_2 (g) at anode. The electrolytic solution is :

Assertion (A): Magnesium can be obtained by the electronlysis of aqueous solution of MgCl_(2) . Reason (R ): The electrode potential of Mg^(2+) is much higher than H^(o+) .

(a). Explain why electrolysis of an aqueous solution of NaCl gives H_(2) at cathode and Cl_(2) at anode. Given E_(Na^(+)//Na)^(@)=-2.71V,E_(H_(2)O//H_(2)^(@)=-0.83V E_(Cl_(2)//2Cl^(-))^(@)=+1.36V,E_(2H^(+)//(1)/(2)O_(2)//H_(2)O)^(@)=+1.23V (b). The resistance of a conductivity cell when filled with 0.05 M solution of an electrolyte X is 100Omega at 40^(@)C . the same conductivity cell filled with 0.01 M solution of electrolyte Y has a resistance of 50Omega . The conductivity of 0.05M solution of electrolyte X is 1.0xx10^(-4)scm^(-1) calculate (i). Cell constant (ii). conductivity of 0.01 M Y solution (iii). Molar conductivity of 0.01 M Y solution.

Assertion:In electrolysis of aqueous NaCl the product obtained is H_2 gas. Reason:Gases are liberted faster than the metals.

A : 2 F^(-) + Cl_(2) to 2 Cl^(-) + F_(2) is a reaction having Delta G^0 = -ve . R : Cl_(2) is better oxidizing agent than F_(2) .

Assertion (A) Decomposition of H_(2)O_(2) is a disproportionation reaction. Reason (R ) H_(2)O_(2) molecule simultaneously undergoes oxidation and reduction.

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