Water potential of a flaccid cell will be

Options

A. ​`Psi_(w)=Psi_(s)`
​
B. `Psi_(s)=Psi_(rho)`
C. `Psi_(w)=0`
D. Ψ w=Ψ s-Ψ p

Explanation

To determine the water potential of a flaccid cell, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Flaccid Cells**: A flaccid cell is one that has lost water, resulting in a decrease in turgor pressure. This typically occurs when the cell is placed in a hypertonic solution, causing water to move out of the cell.

2. **Identify Water Movement**: When a plant cell is in a hypertonic solution, water moves out of the cell through a process called exoosmosis. This leads to a reduction in the volume of the cell's protoplast (the living part of the cell).

3. **Effects on Pressure Potential**: The loss of water from the cell results in a decrease in turgor pressure (pressure potential, denoted as Psi P). In a flaccid cell, the turgor pressure is zero because the protoplast has shrunk away from the cell wall.

4. **Understand Water Potential Equation**: The water potential (Psi W) of a cell can be calculated using the formula:
\[ \Psi W = \Psi S + \Psi P \]
where Psi S is the solute potential and Psi P is the pressure potential.

5. **Calculate Water Potential for Flaccid Cell**: Since the pressure potential (Psi P) of a flaccid cell is zero, the equation simplifies to:
\[ \Psi W = \Psi S + 0 \]
Therefore, the water potential of a flaccid cell is equal to its solute potential (Psi S).

6. **Conclusion**: In a flaccid cell, the water potential is equal to the solute potential, which means that the water potential (Psi W) will be negative or zero, depending on the solute concentration.

### Final Answer:
The water potential of a flaccid cell will be equal to its solute potential (Psi W = Psi S).