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The restoration of turgidity in a plasmo...

The restoration of turgidity in a plasmolysed cell when placed in a hypotonic solution is caused by

A

hytdration

B

electrolysis

C

plasmolysis

D

deplasmolysis

Text Solution

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The correct Answer is:
To solve the question regarding the restoration of turgidity in a plasmolyzed cell when placed in a hypotonic solution, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Plasmolysis**: - Plasmolysis occurs when a plant cell loses water and the cytoplasm shrinks away from the cell wall due to being placed in a hypertonic solution. This results in the cell becoming flaccid and losing turgidity. 2. **Hypotonic Solution**: - A hypotonic solution has a lower concentration of solutes compared to the inside of the cell. When a plasmolyzed cell is placed in a hypotonic solution, the concentration of water outside the cell is higher than inside. 3. **Water Movement**: - Due to osmosis, water will move from the area of higher concentration (hypotonic solution) to the area of lower concentration (inside the cell). This influx of water will cause the cell to swell. 4. **Restoration of Turgidity**: - As water enters the cell, it fills the vacuole and pushes the cytoplasm against the cell wall, restoring the cell's turgidity. This process is known as "deplasmolysis." 5. **Conclusion**: - The correct answer to the question is that the restoration of turgidity in a plasmolyzed cell when placed in a hypotonic solution is caused by "deplasmolysis." ### Final Answer: The answer is option D: Deplasmolysis.
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Knowledge Check

  • When a cell is placed in a hypotonic solution :

    A
    solute exits the cell to equalize the concentration on both sides of the membrane
    B
    water exits the cell toward the area of lower solute concentration
    C
    water enters the cell toward the area of higher solute concentration
    D
    solute exits and water enters the cell
  • When a cell is placed in a hypertonic solution:

    A
    solute exits the cell to equalize the concentration on both sides of the membrane
    B
    water exits the cell toward the area of lower solute concentration
    C
    water exits the cell toward the area of higher solute concentration
    D
    solute exits and water enters the cell
  • A cell placed in hypertonic solution will :

    A
    Shrink
    B
    Show exosmosis
    C
    Show endosmosis
    D
    No change in size and shape
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