In a monohybrid cross between two heterozygous individuals, percentage of pure homozygous individuals obtained in `F_(1)` generation will be

Options

A. `25 %`
B. `50 %`
C. `75 %`
D. `100 %`

Explanation

To solve the problem of finding the percentage of pure homozygous individuals obtained in the F1 generation from a monohybrid cross between two heterozygous individuals, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Genotypes of Parents**:
In a monohybrid cross, we consider one trait. Here, we have two heterozygous individuals, which means both parents have the genotype Tt (where T is the dominant allele and t is the recessive allele).

2. **Determine Gametes**:
Each parent can produce two types of gametes: T (dominant) and t (recessive). Therefore, the gametes from both parents are:
- Parent 1: T, t
- Parent 2: T, t

3. **Set Up a Punnett Square**:
We can use a Punnett square to visualize the possible combinations of gametes from both parents. The Punnett square will look like this:

```
T t
----------------
T | TT | Tt |
----------------
t | Tt | tt |
----------------
```

4. **Identify the Genotypes of the Offspring**:
From the Punnett square, we can see the following genotypes for the offspring:
- TT (homozygous dominant)
- Tt (heterozygous)
- Tt (heterozygous)
- tt (homozygous recessive)

5. **Count the Genotypes**:
Now, we can count the number of homozygous and heterozygous individuals:
- Homozygous (TT and tt): 2 (1 TT and 1 tt)
- Heterozygous (Tt): 2

6. **Calculate the Percentage of Homozygous Individuals**:
To find the percentage of homozygous individuals in the F1 generation, we take the number of homozygous individuals and divide it by the total number of individuals, then multiply by 100:
- Total individuals = 4 (TT, Tt, Tt, tt)
- Homozygous individuals = 2 (TT and tt)
- Percentage of homozygous individuals = (2/4) * 100 = 50%

### Final Answer:
The percentage of pure homozygous individuals obtained in the F1 generation is **50%**.