On crossing two heterozygous tall plants (Tt), a total of 500 plants were obtained in `F_(1)` generation. What will be the respective number of tall and dwarf plants obtained of `F_(1)` generation ?

Options

A. `375,125`
B. `250,250`
C. `475,25`
D. `350,150`

Explanation

To solve the problem of determining the number of tall and dwarf plants obtained in the F1 generation from a cross between two heterozygous tall plants (Tt), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Genetic Cross**:
- We are crossing two heterozygous tall plants, which means both parents have the genotype Tt (where T is the dominant allele for tallness and t is the recessive allele for dwarfness).

2. **Determine the Possible Gametes**:
- Each parent can produce two types of gametes: T (tall) and t (dwarf).
- Therefore, the gametes from both parents will be:
- Parent 1: T, t
- Parent 2: T, t

3. **Create a Punnett Square**:
- Set up a Punnett square to visualize the offspring:
```
T t
----------------
T | TT | Tt |
----------------
t | Tt | tt |
----------------
```
- From the Punnett square, we can see the possible genotypes of the offspring:
- TT (homozygous tall)
- Tt (heterozygous tall)
- Tt (heterozygous tall)
- tt (homozygous dwarf)

4. **Count the Genotypes**:
- The genotypes from the Punnett square yield:
- 1 TT (tall)
- 2 Tt (tall)
- 1 tt (dwarf)

5. **Calculate the Phenotypic Ratio**:
- The phenotypic ratio of tall to dwarf plants is:
- Tall (TT + Tt) = 3
- Dwarf (tt) = 1
- Therefore, the ratio is 3:1.

6. **Calculate the Number of Tall and Dwarf Plants**:
- Since there are a total of 500 plants, we can calculate the number of tall and dwarf plants:
- Total plants = 500
- Number of tall plants = (3/4) * 500 = 375
- Number of dwarf plants = (1/4) * 500 = 125

### Final Answer:
- The respective number of tall and dwarf plants obtained in the F1 generation is:
- Tall plants: 375
- Dwarf plants: 125