The percentage of ab gamete produced by AaBb parent will be

Options

A. `25 %`
B. `50 %`
C. `75 %`
D. `12.5 %`

Explanation

To find the percentage of the ab gamete produced by an AaBb parent, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Genotype**: The parent genotype is AaBb, where 'A' and 'a' are alleles for one gene, and 'B' and 'b' are alleles for another gene.

2. **Determine the Number of Gametes**: The number of different gametes that can be produced by a parent with two heterozygous genes can be calculated using the formula \(2^n\), where \(n\) is the number of heterozygous gene pairs. In this case, we have:
- \(n = 2\) (for Aa and Bb)
- Therefore, the number of gametes = \(2^2 = 4\).

3. **List the Possible Gametes**: The possible combinations of gametes from the AaBb parent are:
- AB
- Ab
- aB
- ab

4. **Count the Desired Gamete**: We are interested in the 'ab' gamete. From the list of gametes, we can see that 'ab' is one of the four possible gametes.

5. **Calculate the Percentage**: To find the percentage of the 'ab' gamete, we use the formula:
\[ \text{Percentage of ab gamete} = \left(\frac{\text{Number of ab gametes}}{\text{Total number of gametes}}\right) \times 100 \]
Substituting the values:
\[ \text{Percentage of ab gamete} = \left(\frac{1}{4}\right) \times 100 = 25\% \]

### Final Answer:
The percentage of the ab gamete produced by an AaBb parent is **25%**.

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