The given Punnett's square represents to Pattern of inheritance in a dihybrid cross where yellow (Y) and round (R) seed condition in dominant over white (y) and wrinkled (r) seed condition
`{:(" YR Yr yR yr"),("YR F J N R"),("Yr G K O S"),("yR H L P T"),("yr I M Q U"):}`
A plant of type 'H' will produce seeds with the genotype identical to seeds produced by the plants of

Options

A. Type M
B. Type J
C. Type P
D. Type N

Explanation

To solve the problem regarding the dihybrid cross represented in the given Punnett square, we need to identify the genotype of plant type 'H' and find out which other plant type produces seeds with an identical genotype. Here’s a step-by-step breakdown of the solution:

### Step 1: Understand the Genotypes
The dominant traits are yellow seeds (Y) and round seeds (R), while the recessive traits are white seeds (y) and wrinkled seeds (r). The genotypes can be represented as follows:
- Yellow and Round: YYRR, YYRr, YyRR, YyRr
- White and Wrinkled: yyrr, yyRr, Yyrr, YyRr

### Step 2: Identify the Genotype of Plant Type 'H'
From the Punnett square provided, we need to locate plant type 'H'. According to the transcript, type 'H' corresponds to the genotype:
- Type H: YyRR

### Step 3: Compare with Other Types
Next, we need to compare the genotype of type 'H' (YyRR) with the other types provided in the options:
- Type J: YYRr
- Type M: YyRr
- Type P: yyRR
- Type N: YyRR

### Step 4: Identify the Matching Type
We see that:
- Type H (YyRR) matches with Type N (YyRR).

### Step 5: Conclusion
Thus, a plant of type 'H' will produce seeds with the genotype identical to the seeds produced by the plants of type N.

### Final Answer
The correct answer is **Type N**.

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