A man having the genotype EEFfGgHH can produce P number of genetically different sperms, and a woman of genotype liLLMmNn can generate Q number of genetically different eggs. Determine the values P and Q.
a. P = 4, Q = 4
b. P = 4,Q = 8
c. P = 8, Q = 4
d. P = 8,Q = 8

Options

A. P = 4, Q = 4
B. P = 4,Q = 8
C. P = 8, Q = 4
D. P = 8,Q = 8

Explanation

To determine the number of genetically different sperms (P) produced by a man with the genotype EEFfGgHH and the number of genetically different eggs (Q) produced by a woman with the genotype IiLLMmNn, we can follow these steps:

### Step 1: Identify the heterozygous gene pairs for the man.
- The man's genotype is EEFfGgHH.
- In this genotype:
- E is homozygous (EE)
- F is heterozygous (Ff)
- G is heterozygous (Gg)
- H is homozygous (HH)

Thus, the heterozygous pairs are Ff and Gg. Therefore, there are **2 heterozygous pairs**.

### Step 2: Calculate the number of genetically different sperms (P) using the formula.
- The formula to calculate the number of different gametes is \(2^n\), where \(n\) is the number of heterozygous pairs.
- Here, \(n = 2\).
- Therefore, \(P = 2^2 = 4\).

### Step 3: Identify the heterozygous gene pairs for the woman.
- The woman's genotype is IiLLMmNn.
- In this genotype:
- I is heterozygous (Ii)
- L is homozygous (LL)
- M is heterozygous (Mm)
- N is heterozygous (Nn)

Thus, the heterozygous pairs are Ii, Mm, and Nn. Therefore, there are **3 heterozygous pairs**.

### Step 4: Calculate the number of genetically different eggs (Q) using the formula.
- Using the same formula \(2^n\), where \(n\) is the number of heterozygous pairs:
- Here, \(n = 3\).
- Therefore, \(Q = 2^3 = 8\).

### Conclusion
- The values are \(P = 4\) and \(Q = 8\).
- Thus, the correct answer is option **b. P = 4, Q = 8**.

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