Result of a cross between a normal homozygous female and a haemophiliac male would be

Options

A. normal males and normal females
B. haemophilic males and normal females
C. normal males and carrier females
D. haemophilic males and carrier females

Explanation

To solve the question regarding the result of a cross between a normal homozygous female and a hemophiliac male, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Genotypes**:
- A normal homozygous female has the genotype **XX** (both X chromosomes are normal).
- A hemophiliac male has the genotype **X^H Y** (one X chromosome carries the hemophilia allele).

2. **Determine Gametes**:
- The normal homozygous female can produce gametes that are all **X** (since both X chromosomes are normal).
- The hemophiliac male can produce two types of gametes: **X^H** (hemophilia allele) and **Y** (normal Y chromosome).

3. **Set Up the Punnett Square**:
- Create a Punnett square to visualize the possible combinations of gametes from the parents.
- The gametes from the female (XX) will be on one side and the gametes from the male (X^H Y) on the other side.

| | X | X |
|---------|-------|-------|
| **X^H** | X X^H | X X^H |
| **Y** | X Y | X Y |

4. **Analyze the Offspring**:
- From the Punnett square, we can see the possible genotypes of the offspring:
- **X X^H**: This represents a carrier female (normal phenotype but a carrier of hemophilia).
- **X Y**: This represents a normal male (normal phenotype).

5. **Summarize the Results**:
- The offspring from this cross will be:
- **50% carrier females (X X^H)**
- **50% normal males (X Y)**

### Conclusion:
The result of the cross between a normal homozygous female and a hemophiliac male would yield normal males and carrier females.