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Match column I with column II and select...

Match column I with column II and select the correct option from the given codes
`{:(,"Column I",,"Column II"),("A.","Autopolyploidy","(i)","2n+1"),("B.","Trisomy","(ii)","AAAA"),("C.","Allopolyploidy","(iii)","AABB"),("D.","Nullisomy","(iv)","2n-2"):}`

A

A-(ii),B-(i),C-(iii),D-(iv)

B

A-(iv),B-(i),C-(ii),D-(iii)

C

A-(ii),B-(iv),C-(iii),D-(i)

D

A-(ii),B-(i),C-(iv),D-(iii)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of matching Column I with Column II, we will analyze each term in Column I and find its corresponding match in Column II. ### Step-by-Step Solution: 1. **Understanding Autopolyploidy (A)**: - Autopolyploidy refers to a condition where an organism has more than two sets of chromosomes derived from a single species. - This can be represented as "AAAA" or "4n" (where n is the basic number of chromosomes). - **Match**: Autopolyploidy (A) → (ii) AAAA 2. **Understanding Trisomy (B)**: - Trisomy is a genetic disorder where there is an extra chromosome, leading to a total of 47 chromosomes instead of the normal 46. - This can be expressed as "2n + 1" (where n is the haploid number of chromosomes). - **Match**: Trisomy (B) → (i) 2n + 1 3. **Understanding Allopolyploidy (C)**: - Allopolyploidy occurs when an organism has multiple sets of chromosomes from different species, resulting in a hybrid genome. - This can be represented as "AABB" (indicating two different genomes). - **Match**: Allopolyploidy (C) → (iii) AABB 4. **Understanding Nullisomy (D)**: - Nullisomy is the absence of both chromosomes of a homologous pair, resulting in a total of 2n - 2 chromosomes. - **Match**: Nullisomy (D) → (iv) 2n - 2 ### Final Matches: - A → (ii) AAAA - B → (i) 2n + 1 - C → (iii) AABB - D → (iv) 2n - 2 ### Conclusion: The correct matches are: - A (Autopolyploidy) → (ii) AAAA - B (Trisomy) → (i) 2n + 1 - C (Allopolyploidy) → (iii) AABB - D (Nullisomy) → (iv) 2n - 2 ### Selected Option: The correct option from the given codes is: - A → (ii), B → (i), C → (iii), D → (iv) ---
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