Home
Class 12
BIOLOGY
Study the two cases carefully, What wou...

Study the two cases carefully, What would be the correct interpretation of the two cases ?
`{:("Case","Mother","Father","Children"),("Case I","With disease","Normal","Sons always with disease"),("Case II","With disease","Normal","Sons and daughters could show disease"):}`

A

`{:("Case I : X-linked recessive disease"),("Case II : Autosomal recessive disease"):}`

B

`{:("Case I : Y-linked recessive disease"),("Case II : X-linked recessive disease"):}`

C

Case I and II : X-linked recessive disease

D

`{:("Case I : Y-linked dominant disease"),("Case II : Autosomal dominant disease"):}`

Text Solution

AI Generated Solution

The correct Answer is:
To interpret the two cases provided in the question, we will analyze the inheritance patterns based on the information given about the parents and their children. ### Step-by-Step Solution: 1. **Understanding Case I**: - In Case I, the mother has the disease, and the father is normal. - The children (specifically the sons) always have the disease. - This suggests that the disease is passed from the mother to the sons, indicating a pattern of inheritance where the mother contributes the affected allele. 2. **Identifying the Inheritance Pattern in Case I**: - Since only the sons are affected and the father does not pass the disease to his sons, this points towards an X-linked inheritance pattern. - In X-linked recessive diseases, males (XY) are more likely to express the disease because they have only one X chromosome. If the mother (XX) carries the disease allele on one of her X chromosomes, all her sons (XY) will inherit that X chromosome, resulting in them being affected. 3. **Understanding Case II**: - In Case II, the mother has the disease, and the father is normal. - Here, both sons and daughters could potentially show the disease. - This indicates that the disease can be inherited by both sexes, suggesting a different inheritance pattern. 4. **Identifying the Inheritance Pattern in Case II**: - The fact that both sons and daughters can show the disease means that it is likely not X-linked. - This pattern suggests that the disease is autosomal, meaning it is located on one of the non-sex chromosomes (autosomes). - Since both males and females can inherit the disease, it is likely an autosomal recessive condition, where both parents must carry at least one copy of the recessive allele for the children to express the disease. 5. **Conclusion**: - Therefore, the correct interpretation is: - **Case I**: X-linked recessive disease (sons always affected). - **Case II**: Autosomal recessive disease (sons and daughters could show disease). ### Final Answer: - **Case I**: X-linked recessive disease. - **Case II**: Autosomal recessive disease.

To interpret the two cases provided in the question, we will analyze the inheritance patterns based on the information given about the parents and their children. ### Step-by-Step Solution: 1. **Understanding Case I**: - In Case I, the mother has the disease, and the father is normal. - The children (specifically the sons) always have the disease. - This suggests that the disease is passed from the mother to the sons, indicating a pattern of inheritance where the mother contributes the affected allele. ...
Promotional Banner

Topper's Solved these Questions

  • PRINCIPLES OF INHERITANCE & VARIATION

    NCERT FINGERTIPS ENGLISH|Exercise EXEMPLAR|17 Videos
  • PRINCIPLES OF INHERITANCE & VARIATION

    NCERT FINGERTIPS ENGLISH|Exercise Assertion-Reason|15 Videos
  • PRINCIPLES OF INHERITANCE & VARIATION

    NCERT FINGERTIPS ENGLISH|Exercise Principles Of Inheritance & Variation|167 Videos
  • PRACTICE PAPERS

    NCERT FINGERTIPS ENGLISH|Exercise Practice paper|150 Videos
  • REPRODUCTION IN ORGANISM

    NCERT FINGERTIPS ENGLISH|Exercise All Questions|137 Videos

Similar Questions

Explore conceptually related problems

In which of the following bacterial diseases , intestinal perforation and death occur in severe cases ?

A diseased man marries a normal woman.They get three daughters and five sons were normal . The gene of this disease is :

A diseased man marries a normal woman.They get three daughters and five sons were normal . The gene of this disease is :

A ray of light is incident as a normal ray on the surface of separation of two different mediums. What is the value of the angle of incidence in this case ?

A diseases man marries a normal woman .they get three daughters and five sons ,All the daughters were diseased and sons were normal .the gene of this disease is

A man with a certain disease marries a normal woman. They have eight children (3 daughters and 5 sons). All the daughters suffer from their father's disease but none of the sons are affected. Which of the following mode of inheritance do you suggest for this disease?

In all the given cases block are in contact and the forces are applied as shown. All the surfaces are smooth. Then in whhich of the following cases, normal reaction between the two blocks is zero.

The records of a hospital show that 10% of the cases of a certain disease are fatal. If 6 patients are suffering from the disease, then the probability that only three will die is

Each of the following questions/statements has four suggested answers. rewrite the correct answer in each case: Chancroid is a sexually transmitted disease caused by

State the effects of a force applied on (i) a non rigid, and (ii) a rigid body. How does the effect of the force differ in the two cases ?