In Mendelian dihybrid cross when heterozygous round Yellow are self crossed, Round Green offsprings are represented by the genotype

Options

A. a) RrYy,RrYY,RRYy
B. b) Rryy,RRyy,rryy
C. c) Rryy,Rryy
D. d) RrYy,rryy,Rryy

Answer

To solve the question regarding the genotype of round green offspring from a Mendelian dihybrid cross of heterozygous round yellow seeds, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Traits and Their Alleles**:
- The two traits involved are seed shape and seed color.
- Round shape (R) is dominant over wrinkled shape (r).
- Yellow color (Y) is dominant over green color (y).

2. **Determine the Genotype of the Parents**:
- Since the parents are heterozygous for both traits, their genotype will be RrYy (capital R for round, small r for wrinkled, capital Y for yellow, and small y for green).

3. **Set Up a Punnett Square**:
- To find the possible genotypes of the offspring, we create a Punnett square. Each parent can produce gametes that combine the alleles for both traits.
- The gametes from one parent (RrYy) can be: RY, Ry, rY, and ry.
- The gametes from the other parent (RrYy) will be the same: RY, Ry, rY, and ry.

4. **Fill in the Punnett Square**:
- The Punnett square will have 16 boxes (4x4), and we fill it in with the combinations of the gametes from both parents.

5. **Identify the Genotypes for Round Green Offspring**:
- The round green phenotype will occur when the offspring have at least one dominant allele for round shape (R) and two recessive alleles for green color (yy).
- The possible genotypes for round green offspring are:
- RRyy (homozygous round, homozygous green)
- Rryy (heterozygous round, homozygous green)

6. **Conclusion**:
- The genotypes of the round green offspring are RRyy and Rryy.