`2n = 16` is in a primary spermatocyte which is in metaphase of first meiotic division. What shal be the total number of chromatids in each of the secondary spermatocyte?

Options

A. 16
B. 24
C. 32
D. 8

Explanation

To solve the problem, we need to determine the total number of chromatids in each secondary spermatocyte when the primary spermatocyte has a diploid number of chromosomes represented by \(2n = 16\).

### Step-by-Step Solution:

1. **Identify the Diploid Number (2n)**:
- Given that \(2n = 16\), this means the diploid number of chromosomes in the primary spermatocyte is 16.

2. **Determine the Haploid Number (n)**:
- The haploid number of chromosomes (n) is half of the diploid number. Therefore, we calculate:
\[ n = \frac{2n}{2} = \frac{16}{2} = 8 \]
- This means each secondary spermatocyte will have 8 chromosomes.

3. **Understand Chromatid Structure**:
- During the metaphase of the first meiotic division, each chromosome is made up of two sister chromatids. Thus, each of the 8 chromosomes in the secondary spermatocyte will consist of 2 chromatids.

4. **Calculate the Total Number of Chromatids**:
- Since each of the 8 chromosomes has 2 chromatids, we calculate the total number of chromatids as follows:
\[ \text{Total chromatids} = \text{Number of chromosomes} \times \text{Number of chromatids per chromosome} = 8 \times 2 = 16 \]

5. **Conclusion**:
- Therefore, the total number of chromatids in each secondary spermatocyte is 16.

### Final Answer:
The total number of chromatids in each secondary spermatocyte is **16**.

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