Match column I with column II and select the correct option from the given codes.
`{:("Column I", "Column II"),("Mercury", (i)"Methaemoglobinemia"("or Blue baby syndrome")),("Nitrate", (ii) "Black foot disease"),("Arsenic", (iii)"Itai-itai disease"),("Cadmium",(iv)"Minamata disease"):}`

Options

A. A-(iv), B-(i), C-(ii), D-(iii)
B. A-(iv), B-(i), C-(iii), D-(ii)
C. A-(ii), B-(iii), C-(i), D-(iv)
D. A-(ii), B-(iv), C-(i), D-(iii)

Answer

To solve the problem of matching Column I with Column II, we will analyze each element in Column I and identify the corresponding disease from Column II.

### Step-by-Step Solution:

1. **Identify the first element in Column I: Mercury**
- Mercury is known to cause **Minamata disease**. This disease is characterized by neurological damage and is particularly harmful to children.
- **Match:** Mercury → Minamata disease (iv)

2. **Identify the second element in Column I: Nitrate**
- Nitrate is associated with **Methaemoglobinemia**, also known as **Blue baby syndrome**. This condition affects the ability of blood to carry oxygen, leading to a bluish coloration in infants.
- **Match:** Nitrate → Methaemoglobinemia (i)

3. **Identify the third element in Column I: Arsenic**
- Arsenic exposure can lead to **Black foot disease**, which is characterized by gangrene of the feet.
- **Match:** Arsenic → Black foot disease (ii)

4. **Identify the fourth element in Column I: Cadmium**
- Cadmium is linked to **Itai-itai disease**, which is a painful condition caused by cadmium poisoning, leading to severe bone and kidney damage.
- **Match:** Cadmium → Itai-itai disease (iii)

### Summary of Matches:
- Mercury → Minamata disease (iv)
- Nitrate → Methaemoglobinemia (i)
- Arsenic → Black foot disease (ii)
- Cadmium → Itai-itai disease (iii)

### Final Matching:
- A (Mercury) → iv (Minamata disease)
- B (Nitrate) → i (Methaemoglobinemia)
- C (Arsenic) → ii (Black foot disease)
- D (Cadmium) → iii (Itai-itai disease)

### Correct Option:
The correct matching corresponds to option 1:
- A → 4
- B → 1
- C → 2
- D → 3