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The distance of a galaxy from the earth ...

The distance of a galaxy from the earth is of the order of `10^(25)m`. The time taken by light to reach the earth from the galaxy is

A

`A. 3xx10^(14)s`

B

`B. 3xx10^(16)s`

C

C. `3xx10^(18)s`

D

`D. 3xx10^(20)s`

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The correct Answer is:
To solve the problem of finding the time taken by light to reach Earth from a galaxy that is \(10^{25}\) meters away, we will follow these steps: ### Step 1: Write down the given values We know: - Distance \(d = 10^{25}\) meters - Speed of light \(c = 3 \times 10^{8}\) meters per second ### Step 2: Use the formula for time The time \(t\) taken for light to travel a distance can be calculated using the formula: \[ t = \frac{d}{c} \] ### Step 3: Substitute the values into the formula Now, substituting the known values into the formula: \[ t = \frac{10^{25}}{3 \times 10^{8}} \] ### Step 4: Simplify the expression We can simplify the expression by separating the powers of ten: \[ t = \frac{10^{25}}{10^{8}} \times \frac{1}{3} = 10^{(25-8)} \times \frac{1}{3} = 10^{17} \times \frac{1}{3} \] ### Step 5: Calculate the numerical value Calculating \(\frac{1}{3}\) gives approximately \(0.33\), so: \[ t \approx 0.33 \times 10^{17} \text{ seconds} \] ### Step 6: Express in scientific notation We can express \(0.33\) as \(3.33\) and adjust the power of ten: \[ t \approx 3.33 \times 10^{16} \text{ seconds} \] ### Step 7: Round to match the options Since the options provided are in the form of \(3 \times 10^{16}\), we can round \(3.33\) to \(3\): \[ t \approx 3 \times 10^{16} \text{ seconds} \] ### Conclusion Thus, the time taken by light to reach Earth from the galaxy is approximately: \[ \text{Option B: } 3 \times 10^{16} \text{ seconds} \] ---

To solve the problem of finding the time taken by light to reach Earth from a galaxy that is \(10^{25}\) meters away, we will follow these steps: ### Step 1: Write down the given values We know: - Distance \(d = 10^{25}\) meters - Speed of light \(c = 3 \times 10^{8}\) meters per second ### Step 2: Use the formula for time ...
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