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The dimensional formula of physical quan...

The dimensional formula of physical quantity is `[M^(a)L^(b)T^(c)]`.Then that physical quantity is

A

A. surface tension if a=1,b=1,c=-2

B

B. force if a=1,b=1,c=2

C

C. angular frequency if a=0,b=0,c=-1

D

D. spring constant if a=1,b=-1,c=-2

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To determine which physical quantity corresponds to the given dimensional formula \([M^a L^b T^c]\), we will analyze each option provided based on their dimensional formulas. ### Step 1: Understand the given dimensional formula The dimensional formula is given as \([M^a L^b T^c]\), where: - \(M\) represents mass, - \(L\) represents length, - \(T\) represents time. ### Step 2: Analyze each option #### Option A: Surface Tension - **Unit**: Newton per meter (N/m) - **Dimensional formula**: \[ \text{Newton} = \text{kg} \cdot \text{m/s}^2 = M^1 L^1 T^{-2} \] Therefore, surface tension: \[ \text{Surface Tension} = \frac{M^1 L^1 T^{-2}}{L^1} = M^1 L^0 T^{-2} \] This gives us \(a = 1\), \(b = 0\), \(c = -2\). #### Option B: Force - **Unit**: Newton (N) - **Dimensional formula**: \[ \text{Newton} = \text{kg} \cdot \text{m/s}^2 = M^1 L^1 T^{-2} \] Here, we have \(a = 1\), \(b = 1\), \(c = -2\). #### Option C: Angular Frequency - **Unit**: Radians per second (1/s) - **Dimensional formula**: \[ \text{Angular Frequency} = \frac{1}{T} = M^0 L^0 T^{-1} \] Thus, \(a = 0\), \(b = 0\), \(c = -1\). #### Option D: Spring Constant - **Unit**: Newton per meter (N/m) - **Dimensional formula**: \[ \text{Spring Constant} = \frac{\text{Force}}{\text{Length}} = \frac{M^1 L^1 T^{-2}}{L^1} = M^1 L^0 T^{-2} \] This gives us \(a = 1\), \(b = 0\), \(c = -2\). ### Step 3: Compare with the options Now let's compare the results with the options provided: - **Option A**: \(a = 1\), \(b = 0\), \(c = -2\) (Incorrect) - **Option B**: \(a = 1\), \(b = 1\), \(c = -2\) (Incorrect) - **Option C**: \(a = 0\), \(b = 0\), \(c = -1\) (Correct) - **Option D**: \(a = 1\), \(b = 0\), \(c = -2\) (Incorrect) ### Conclusion The correct answer is **Option C: Angular Frequency**, which has the dimensional formula \(M^0 L^0 T^{-1}\).

To determine which physical quantity corresponds to the given dimensional formula \([M^a L^b T^c]\), we will analyze each option provided based on their dimensional formulas. ### Step 1: Understand the given dimensional formula The dimensional formula is given as \([M^a L^b T^c]\), where: - \(M\) represents mass, - \(L\) represents length, - \(T\) represents time. ...
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